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<body>
    <script>
        //柯里化思想
        // add(1,2,3)=add((1)(2)(3))
        //请实现以下效果
        function add(a, b, c) {
            return a + b + c
        }
        // console.log(add.length);

        const res = add(1, 2, 3)
        console.log(res);//6

        //要求声明一个curry函数，函数add经过curry函数的处理后，每次调用只能接收一个参数

        const curry = (fn) => {
            return a => {
                return b => {
                    return c => {
                        return fn(a, b, c)
                    }
                }
            }
        }
        let addCurry = curry(add)

        // console.log(addCurry);
        const res2 = addCurry(1)(2)(3) //6

        console.log(res2);




        // // 几个数相乘
        // const curryTwo = (fn) => {
        //     return function curried(...add) {
        //         if (add.length >= fn.length) {
        //             return fn.apply(this, add)
        //         } else {
        //             return function (...add2) {
        //                 return curried.apply(this, add.concat(add2))
        //             }
        //         }
        //     }
        // }

        // let curry1 = curryTwo(add)
        // console.log(curry1(1)(2)(3));

        const sumFn = (...args) => {
            return args.reduce((a, b) => {
                return a + b 
            })
        }
      let curry1 = function (func) {
            const args = []
            return function res(...rest) {
                if (rest.length === 0) {
                    return func(...args)
                } else {
                    args.push(...rest)
                    return res
                }
            }
        }
        curry1(sumFn)(2)(2)(3)()

    </script>
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